-(3x^2-5y)-4(3x^2+y)=

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Solution for -(3x^2-5y)-4(3x^2+y)= equation:


Simplifying
-1(3x2 + -5y) + -4(3x2 + y) = 0
(3x2 * -1 + -5y * -1) + -4(3x2 + y) = 0
(-3x2 + 5y) + -4(3x2 + y) = 0
-3x2 + 5y + (3x2 * -4 + y * -4) = 0
-3x2 + 5y + (-12x2 + -4y) = 0

Reorder the terms:
-3x2 + -12x2 + 5y + -4y = 0

Combine like terms: -3x2 + -12x2 = -15x2
-15x2 + 5y + -4y = 0

Combine like terms: 5y + -4y = 1y
-15x2 + 1y = 0

Solving
-15x2 + 1y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1y' to each side of the equation.
-15x2 + 1y + -1y = 0 + -1y

Combine like terms: 1y + -1y = 0
-15x2 + 0 = 0 + -1y
-15x2 = 0 + -1y
Remove the zero:
-15x2 = -1y

Divide each side by '-15'.
x2 = 0.06666666667y

Simplifying
x2 = 0.06666666667y

Combine like terms: 0.06666666667y + -0.06666666667y = 0.00000000000
x2 + -0.06666666667y = 0.00000000000

The solution to this equation could not be determined.

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